- This topic has 5 replies, 3 voices, and was last updated 7 years, 3 months ago by
Zhang Gaolu.
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April 11, 2017 at 7:18 am #42967
Zhang Gaolu
ParticipantHello everyone, I want to use single drive mach-zehnder modulator. But do not know how to set parameters in the parameters set. And why there are two biased voltages as it is single-driven. in what is the meaning of conventional in Modulator type option. is the Modulation voltage the half-wave voltage? What are the two options in the operation mode? can anyone help me ?
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April 30, 2017 at 7:05 pm #43196
stack programer
ParticipantHi, i had same problem i concluded this.you can see good info about transfer function mach-zehnder here :opticsystem_component_library.pdf
https://drive.google.com/open?id=0Bxkt-d32S34gblFOVnNUSlF4TUEphi0 is 0 radians for a conventional modulator and π radians for
phase-shift modulatorso i test modulation type with bit sequence 01:
when bit sequence is 0 in phase shift modulation amplitude is high and when bit sequence is 0 amplitude is negative or low.https://drive.google.com/open?id=0Bxkt-d32S34gaEJsVW8tRkxOOHc
but for conventional is vice versa phase shift-
April 30, 2017 at 11:16 pm #43201
Zhang Gaolu
Participantthank you so much
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May 6, 2017 at 2:23 pm #43305
Dr. Dhiman Kakati
ParticipantHi Zhang Gaolu,
Do not get confused with the two bias voltage. Each MZM will have two bias voltages These are required for operating the MZM in Peak, Quadrature and null point of operation. Depending on the point of operation you have to set the voltages. the single drive means only one RF voltages. i.e. Among the two arms of Mach-Zehnder interferometer structure, RF voltage is applies at only one arm. Please go through the literature of MZM. I can suggest you go through the book “Broadband optical modulators” edited by Antao Chen and Edmund Murphy.Half-wave voltage means the voltage required to make a phase shift of pi/2.
for the 3rd Question I would suggest you go through the book I mentioned above. Then only you will understand.
Regards,
Dhiman-
May 6, 2017 at 2:26 pm #43306
Dr. Dhiman Kakati
ParticipantPlease Go through the attached Image. Here V1 and V2 are the bias voltages
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May 6, 2017 at 9:44 pm #43309
Zhang Gaolu
Participantthank you so much.i hinave already solve the problem.thank you again
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