Beating of optical signals by photodiode
Kindly see question from one of my reviewer.
For reference; RFmodulation frequency is used to generate by external modulation optical bands is 5GHz.The optical signal shown in optical spectrum is amplified with optical amplifier of 30 dB gain before detection by diode.
1 and 2 are 1st order optical side bands
6 and 4 are 2nd order optical side bands
And 5 and 3 are 6th order bands.
20Ghz Rf signal is generated from beating (6,4)
40 Ghz from beating (5,6) and (4,3)
Why is 5Ghz signal that would have been result of beating (6,1) and (2,4) absent.
Similarly Why is 15Ghz signal that would have been result of beating (6,2) and (1,4) absent.
Further why power of 40Ghz signal greater than that of 10Ghz signal in Rf spectrum.
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