March 15, 2016 at 10:35 am
#32871
HELLO RANJEET
Well i find the comment posted by gokul boro very useful in this regard. If you see the the frequency spacing between two consecutive subcarriers is 1.25 GHz and he’s right that the subcarriers are numbered like 1,2..so on . By multiplying the each of them by frequency gap, we get 1.25 GHZ 2.50 GHz respectively. I feel this should be enough for you to understand.
Thanks and regards
Categories
- All
-
Knowledge
Contains a detailed Q&A knowledge base. -
General
All non-technical questions. -
System
Optical system design and analysis. -
Instrument
Communicate and control different kinds of instruments. -
SPICE
Opto-electronic circuit design. -
FDTD
Finite-Difference Time-Domain simulation. -
BPM
Beam Propagation Method analysis and design. -
Grating
Fiber optic grating simulation. -
Fiber
Optical fiber design and characterization. -
Exchange
Users can exchange design files.
(Matlab, C++, etc.)