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I have a doubt regarding optical comb using optoelectronic scheme.
In an optical comb, when the 1×2 fork equally divides the RF power, why there is a difference in RF gain? One electrical amplifier with a gain of 10 dB, and another electrical amplifier_1 with a gain of 9.33 dB? is there any reason for this usage of different gains? please let me know. I have enclosed the image for this.regards
Vamsy
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