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August 24, 2015 at 2:17 am
#24001
Dear Farhad, In the first two outputs, the signal from the input 3 is there considering the insertion loss for each input. In addition, the signal from input port of each of these outputs (outpus 1 and 2) can also exist in their output depending on their return loss. So the signal from Input 3 is splitted between output 1 and output 2.
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