Graphics OCDMA-PON

To figure 5 and 6 implemented a function and then went picking results, then it was just in matlab.
Figure 5 data:
unction[p] = pbreak[m,w,g]

(m,w,g) (m,w,g)
‘blue’ ‘red’
(10,8,1) (10,4,1)
(15,8,2) (15,4,2)
(20,8,3) (20,4,3)

‘blue’
Pbreak(10,8,1) = 6.8893e-08 Pbreak(10,8,2) = 4.7463e-15
Pbreak(15,8,1) = 4.8177e-10 Pbreak(15,8,2) = 2.3210e-19
Pbreak(20,8,1) = 2.4611e-11 Pbreak(20,8,2) = 6.0568e-22
Pbreak(25,8,1) = 2.8664e-12 Pbreak(25,8,2) = 8.2161e-24
Pbreak(30,8,1) = 5.2968e-13 Pbreak(30,8,2) = 2.8056e-25

Pbreak(10,8,3) = 3.2699e-22
Pbreak(15,8,3) = 1.1182e-28
Pbreak(20,8,3) = 1.4906e-32
Pbreak(25,8,3) = 2.3550e-35
Pbreak(30,8,3) = 1.4861e-37
========//========================================================

‘red’
Pbreak(10,4,1) = 2.4802e-05 Pbreak(10,4,2) = 6.1512e-10
Pbreak(15,4,1) = 3.8156e-06 Pbreak(15,4,2) = 1.4559e-11
Pbreak(20,4,1) = 1.0750e-06 Pbreak(20,4,2) = 1.1556e-12
Pbreak(25,4,1) = 4.1173e-07 Pbreak(25,4,2) = 1.6952e-13
Pbreak(30,4,1) = 1.9005e-07 Pbreak(30,4,2) = 3.6119e-14

Pbreak(10,4,3) = 1.5256e-14
Pbreak(15,4,3) = 5.5552e-17
Pbreak(20,4,3) = 1.2423e-18
Pbreak(25,4,3) = 6.9795e-20
Pbreak(30,4,3) = 6.8645e-21

Figure 6 data:

function[p] = pbreak[m,w,g]

(m,w,g) (m,w,g)
‘blue’ ‘blue’
(15,8,0) (15,4,0)
(15,8,5) (15,4,5)
(15,8,10) (15,4,10)
(15,8,15) (15,4,15)
(15,8,20) (15,4,20)

(m,w,g) (m,w,g)
‘red’ ‘red’
(11,8,0) (11,4,0)
(11,8,5) (11,4,5)
(11,8,10) (11,4,10)
(11,8,15) (11,4,15)
(11,8,20) (11,4,20)

Pbreak(15,8,0) = 1 Pbreak(15,4,0) = 1
Pbreak(15,8,5) = 2.5954e-47 Pbreak(15,4,5) = 8.0878e-28
Pbreak(15,8,10)= 6.7361e-94 Pbreak(15,4,10)= 6.5413e-55
Pbreak(15,8,15)= 1.7483e-140 Pbreak(15,4,15)= 5.2904e-82
Pbreak(15,8,20)= 4.5375e-187 Pbreak(15,4,20)= 4.2788e-109

Pbreak(11,8,0) = 1 Pbreak(11,4,0) = 1
Pbreak(11,8,5) = 2.3417e-39 Pbreak(11,4,5) = 9.7932e-25
Pbreak(11,8,10)= 5.4835e-78 Pbreak(11,4,10)= 9.5907e-49
Pbreak(11,8,15)= 1.2841e-116 Pbreak(11,4,15)= 9.3923e-73
Pbreak(11,8,20)= 3.0068e-155 Pbreak(11,4,20)= 9.1981e-97

Now the graphics I could generate in the matlab Figure 5 and 6, please can someone help me with the graph 3.