January 7, 2019 at 10:49 am
#50227
Hello Malik,
Power is the integral of the Poynting vector over the source or observer. In 2D your source is a line not an area so integrating Intensity (W/m^2) over your line (m) would result in your power over your line in fact being W/m. Simply use the power you want, this will set the peak power along your source to match what you want it to be.
Scott
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