I would also like to say that the resulting noise is in Joules/Second or Watts. To convert the noise power to dB·Watts, use 10 times the log of the noise power in watts. If we look at the normalized (B = 1 Hz bandwidth) noise floor equation, we have:
Noisefloor=10×log10(k×T×B)
I am posting a link. You can please refer to it.
http://www.highfrequencyelectronics.com/index.php?option=com_content&view=article&id=553:receiver-sensitivity-and-equivalent-noise-bandwidth&catid=94:2014-06-june-articles&Itemid=189
Regards